JEE Main 2025 · 8 April 2025 · Evening

Based upon JEE Main 2025 — 8 April Evening — full-length mock test

75 questions · 180 minutes · the real marking · built upon the real session paper, question by question. Solve one below, then take the whole paper on the real clock.

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This paper

What you sit down to

Questions: 75 · 25 per subject
Time: 180 minutes, one sitting
Marking: +4 / −1 on A · +4 / 0 on B
Marks: 300

Physics · Section A + Section B100 marks
Chemistry · Section A + Section B100 marks
Mathematics · Section A + Section B100 marks

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Based upon

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ChemistryNumerical · +4 / 0

Resonance in

X_{2} Y

can be represented by the two Lewis structures shown. For the formation of

X_{2} Y

X \equiv X (g) + \frac{1}{2} Y = Y (g) \to X_{2} Y (g)

the enthalpy of formation is

80 kJ mol^{- 1}

. The magnitude of the resonance energy of

X_{2} Y

kJ mol^{- 1}

(nearest integer value).
Given: bond energies of

X \equiv X

X = X

Y = Y

and

X = Y

are

940

410

500

and

602 kJ mol^{- 1}

respectively. Valence of

X

3

and of

Y

2

Two resonance Lewis structures of the linear three-atom species X2Y, joined by a double-headed resonance arrow. In the left structure the terminal X carries a lone pair and a negative charge, is double bonded to a central X that carries a positive formal charge, which is in turn double bonded to Y bearing lone pairs (X=X=Y). In the right structure the terminal X carries a lone pair and is triple bonded to the central X, which carries a positive formal charge and is single bonded to Y bearing lone pairs and a negative charge (X triple-bond X single-bond Y).

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About this paper

Is this the actual JEE Main paper?

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